Web Reference: Instead of maximizing the vertical distance, it is convenient to maximize the squared vertical distance $d^2 (x)= (x^2-x-20)^2$. We cancel the first derivative to find the extrema, $\left (d^2 (x)\right)'=2d (x)d' (x)=0$. In this video I showed how to optimize the vertical distance between two functions The vertical distance is going to be the distance between the y values, so subtract the equations. We'll take the second one and subtract the first one, to keep the distance positive.
YouTube Excerpt: In this video I showed how to optimize the
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