Web Reference: Oct 2, 2012 · You can simply use copy = Object.create(originalObj); but you may want to use copy = JSON.parse(JSON.stringify(originalObj)); to avoid any reference in sub objects (Deep Copy). Jan 16, 2026 · In this blog, we’ll explore the difference between reference and value types, and dive into various methods to clone objects (shallow and deep) without retaining references. Nov 5, 2023 · But did you know that simply assigning an object to a new variable keeps a reference to the original? In this comprehensive guide, we‘ll explore different ways to clone objects in JavaScript without maintaining references.
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